braxas Education learning for the futureA

Ensuring effective marking and feedback in mathematics

braxas Education learning for the futureA

Improvement Prompts

There are 3 types of improvement prompt:

• The reminder prompt – reiterates the learning intention.

• The scaffolded prompt – suggests what could be written to more successfully match the learning intention.

• The example prompt – models a choice of possible improvements, but asks if the child has an idea of his/her own.

braxas Education learning for the futureA

Outcome of a piece of work in Mathematics

Correct Incorrect

Correct, with thorough

understanding

Correct, inefficient methods

Incorrect in part of

process

Lack of prior knowledge/

understanding

Identify next steps/

challenge

Model efficient method with

task set

Incorrect, inefficient methods

Highlight errors/model

efficient method with

task set

Identifyerror in processaddress

appropriately

Identify gap and address appropriately

Effective Feedback

braxas Education learning for the futureA

braxas Education learning for the futureA

• Why can’t 20p be the first coin in the row? 2p 5p 20p 1p 10p

• Why has the 20p always to be the middle coin in the row?

2p 5p 20p 1p 10p• Which coins can we move around to match

the last clue?

braxas Education learning for the futureA

Child B

braxas Education learning for the futureA

Well done• Can you show a quicker way of recording this?• How many 60p candles did you have? _ x 60p How many 85p candles did you have? _ x 85p • 4 x 60p + 2 x 85pDouble 60p = £1.20 Double £1.20 =£ 2.40Now double 85p =

braxas Education learning for the futureA

Child A

braxas Education learning for the futureA

• Is this a likely answer for two numbers both below 200? Explain why? e.g 200 + 200 = 400

615 > 400• 1 7 8 Compare this correct answer with your

1 1617 working out. Where did you go wrong? 3_4_5• 100 70 8 + 100 60 7

braxas Education learning for the futureA

braxas Education learning for the futureA

• How do you know you have found all the possible solutions? E.g. 3 jewels between 2 pirates= 1 pirate will have a single jewel each time. Therefore 3 possible solutions for each pirate because 3 different jewels. Giving 6 possible outcomes.

• Will you always have the same number of solutions if you have 3 different jewels? Why?

• How many outcomes for 4 jewels shared equally between 2 pirates?