2.6B Systems Elimination.notebook October 18, 2018

Warm

State the property or identity.1) 27 + 0 = 27

2) a + 4 = ­11 ­ 4 ­4 a = ­15

I can solve systems of equations by elimination.

3.) What is the first step in solving a system of equations using substitution method?

Let's think about... x + y = 5 x ­ y = 1

Yipee! It's "systems of equations"!

your teacher...lol

Is (14, 5) a solution for

x + 14y = 84 2x ­ 7y = ­7 ??

Solving by elimination:

2x ­ 2y = ­82x + 2y = 4

4x + 3y = 162x ­ 3y = 8

2x ­ 3y = 4­4x + 5y = ­8

5x ­ 3y = 16

4x + 5y = ­2

2.6B Systems Elimination.notebook October 18, 2018

practice due tomorrow~

Systems Elimination Homework (1­8)

I can solve systems of equations by elimination.